five solutions a b c d and e are tested in universal indicator showed pH as 4, 1,11, 7 and 9 respectively which solution is
option:a) neutral
b) strongly alkaline
c) strongly acidic
d) weakly acidic
e) weakly alkaline
Answers
Answered by
81
we know that ph = 7 is neutral
ph>7 = basic
ph<7 = acidic
according to the question,
ph of a= 4
ph of b=1
ph of c= 11
ph of d=7
ph of e=9
so,
a) neutral : solution 'd'
b)strongly alkaline: solution 'c'
c) strongly acidic: solution 'b'
d) weakly acidic: solution 'a'
e) weakly alkaline : solution 'e'
Answered by
33
a) Neutral - 7
b) Strongly alkaline-11
c)Strongly acidic-1
d) weakly acid -
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