Chemistry, asked by pritammondal64, 1 year ago

five solutions a b c d and e are tested in universal indicator showed pH as 4, 1,11, 7 and 9 respectively which solution is
option:a) neutral
b) strongly alkaline
c) strongly acidic
d) weakly acidic
e) weakly alkaline

Answers

Answered by Shreya69614
81

we know that ph = 7 is neutral

ph>7 = basic

ph<7 = acidic

according to the question,

ph of a= 4

ph of b=1

ph of c= 11

ph of d=7

ph of e=9

so,

a) neutral : solution 'd'

b)strongly alkaline: solution 'c'

c) strongly acidic: solution 'b'

d) weakly acidic: solution 'a'

e) weakly alkaline : solution 'e'

Answered by wwwvinaysahucom28
33

a) Neutral - 7

b) Strongly alkaline-11

c)Strongly acidic-1

d) weakly acid -

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