Question

Five square flower beds each of sides 1.4 m are dug on a piece of land 14m long and 16m wide. What is the area of the remaining part of land

Answer 1

Answer:

126m^2

Hope this helps!

Answer 2

❏ Question:-

Five square flower beds each of sides 1.4 m are dug on a piece of land 14m long and 16m wide. What is the area of the remaining part of land

❏ Solution:-

➔Given :-

• side of each square = 1.4 m.
• length of the land =14 m .
• width of the land = 16 m.

➔ Explanation :-

➝ Area of each square shaped flower bed,

$\sf\implies A_{bed}= 1.4^2 \:m^2$

$\sf\implies A_{bed}= 1.96 \:m^2$

Now , Area of such 5 beds is ,

$\sf\implies A_{5\:beds}= 5\times1.96 \:m^2$

$\sf\implies A_{5\:beds}= 9.80 \:m^2$

➝ Area of the Land ,

$\sf\implies A_{Land}= 14\times16 \:m^2$

$\sf\implies A_{Land}=224 \:m^2$

∴ Area of Remaining portion

= (224-9.80) m²

= 213.20 m²

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❏ Formula Used:-

✦RECTANGLE✦

For a rectangle of length l and breadth b,

$\sf\longrightarrow \boxed{Area=length\times breadth}$

$\sf\longrightarrow \boxed{Perimeter=2\times(length+Breadth)}$

$\sf\longrightarrow \boxed{Diagonal=\sqrt{length{}^{2}+Breadth{}^{2}}}$

✦SQUARE✦

For a square of side a ,

$\sf\longrightarrow \boxed{Area=Side{}^{2}}$

$\sf\longrightarrow \boxed{Perimeter=4\times side}$

$\sf\longrightarrow \boxed{Diagonal=\sqrt{2}\times side}$

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