Question

five square flower beds ecah of side 1 m are dug on a peice of land 5 m long and 4 m wide . what is the area of reamaning part of the land?​

Answer 1

Answer:

Area of Remaining part of Land = 15m^2

Step-by-step explanation:

Area of flower square bed  = side × side

⇒ Area of flower square bed = 1 × 1 = 1 m2

Thus, area of 5 square beds = 1 × 5 = 5 m2

Now, Area of the land = Length × Breadth

⇒  Area of the land = 5 × 4 = 20 m2

Now, the remaining part of the land = Area of land – Area of 5 square beds

= 20 – 5

= 15 m2

Answer 2

Appropriate Question :-

Five square flower beds each of side 1 m are dug on a peice of land 5 m long and 4 m wide. What is the area of reamaning part of the land?

$\large\underline{\sf{Solution-}}$

Dimensions of Land

• Length of land = 5 m

• Breadth of land = 4 m

As, Land is in the shape of rectangle.

So, area of land is evaluated as

$\rm \: Area_{(Land)} = Length \times Breadth$

$\rm \: Area_{(Land)} = 5 \times 4$

$\rm\implies \:\boxed{ \rm{ \:Area_{(Land)} = 20 \: {m}^{2} \: \: }}$

Now, Dimensions of flower bed

• Side of flower bed = 1 m

As flower bed is in the shape of square.

So, area of flower bed is evaluated as

$\rm \: Area_{(flower \: bed)} = {(Side)}^{2}$

$\rm \: Area_{(flower \: bed)} = {(1)}^{2}$

$\rm \: Area_{(flower \: bed)} = 1 \: {m}^{2}$

So,

$\rm\implies \:\rm \: \boxed{ \rm{ \:Area_{(5 \: flower \: beds)} = 5 \: {m}^{2} \: }}$

Now,

$\rm \: Area_{(Remaining \: part \: of \: the \: Land)}$

$\rm \: = \: Area_{(Land)} - Area_{(5 \: flower \: beds)}$

$\rm \: = \: 20 - 5$

$\rm \: = \: 15 \: {m}^{2}$

Hence,

$\rm\implies \:\boxed{ \rm{ \:\rm \: Area_{(Remaining \: part \: of \: the \: Land)} = 5 \: {m}^{2} \: \: }}$

$\rule{190pt}{2pt}$

Additional information :-

$\begin{gathered}\begin{gathered}\boxed{\begin {array}{cc}\\ \dag\quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Base\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}d\sqrt {4a^2-d^2}\\ \\ \star\sf Parallelogram =Base\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {array}}\end{gathered}\end{gathered}$