Five students stand in a row such that distance between two successive students is always 5/4m. Find the total distance between the first and the last students.
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The distance between the 1st student and the second student= 5/4m=1.25m
similarly,
distance between the second and third, third and fourth, and fourth and fifth = 5/4m=1.25m
Distance between the first and the last = (1.25+1.25+1.25+1.25)m
= 6m
similarly,
distance between the second and third, third and fourth, and fourth and fifth = 5/4m=1.25m
Distance between the first and the last = (1.25+1.25+1.25+1.25)m
= 6m
kumaranupam595p7d9n9:
Right answer 5
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