Five Students Went For A Hiking Trip Each Of Them Were Carrying Separate Bags Of 33 By 4 Kg Of Rice To 3 By 8 Kg Of Fuel And 4 1 By 2 Kg Of Other Provisions They Got A Man To Help Them Carry The Best But He Could Carry The Maximum Weight Of 42 Kg The Student Decided To Use Him And Also Decided That Each Of Them Will Carry One Of Their Own Back If Each Student Is To Carry The Same Type Of Back Which Of The Three Bags Will Each One Of Them Have To Carry Why Why
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Answer:
They will carry Other Provision bag bags with them.
Step-by-step explanation:
Given:
Weight of Rice bag = 33/4 kg = 8.25 kg
Weight of Fuel Bags = 3/8 kg = 0.375 kg
Weight of other provision bags = 4 1/2 kg = 9/2 kg = 4.5
To find: Bag that each one of them have to carry.
Total weight of bags = 5 × ( Weight of individual bags )
= 5 × ( 33/4 + 3/8 +9/2 )
= 5 × ( 105/8 ) = 525/8 = 65.625 kg
Out of this 42 kg is carried by the helping man
Weight left = 65.625 - 42 = 23.625 kg
This is to be divided equally among 5 students = 23.625/5 = 4.725 kg.
Therefore, They will carry Other Provision bag bags with them.
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