Five times A's age exceeds B's age by 5 years.(¹/9)
th of B's age is half of A's age. Find their
ages
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Answer:
A=10,B = 45
Step-by-step explanation:
5A= B+5
B/9 = A/2
from eq1 we can get A-1 = B/5 so A = B/5 + 1
now B/9 = B/10+ 1/2
B/90 = 1/2
B= 45
Now A = (45+5 )/5
A= 10
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