Question

Five times of a positive integer is equal to 3 less than twice the square of that number. The number is?​

Answer 1

Answer: 3

Step-by-step explanation:

 let the positive integer be x

     5x = 2*x^2 -3

      5 (3) = 2* 3^2 -3 ( by trail and error method)

         15 = 2*9-3

        15=18-3

       15=15

Answer 2

The required number is 3.

Step-by-step explanation:

Given : Five times of a positive integer is equal to 3 less than twice the square of that number.

To find : The number is?​

Solution :

Let the positive integer be x .

According to question,

Five times of a positive integer is equal to 3 less than twice the square of that number

$5x=2x^2-3$

Solving the equation,

$2x^2-5x-3=0$

Apply middle term split,

$2x^2-6x+x-3=0$

$2x(x-3)+1(x-3)=0$

$(x-3)(2x+1)=0$

$x=3,-\frac{1}{2}$

Reject $x=\frac{-1}{2}$

So, the required number is 3.

#Learn more

A number is 7 less than the other and its square is 77 less than the square of the greater number.The smaller number is:​

https://brainly.in/question/13595957