Question

five year ago A age was four times the age of B Five year hence A's age will be twice the age of B .Find their present age

Answer 1

Let the B's age be x
A's age = 4x

Five years ago
A's age = 4x + 5
B's age = x + 5

Five years hence
A's age = 4x + 5 + 5 = 4x + 10
B's age = x + 5 + 5 = x + 10

According to question

4x + 10 = 2(x + 10)
4x + 10 = 2x + 20
2x = 10
x = 5

A's age = 4x + 5
= 25years

B's age = x + 5
= 10years