Question

five year ago a man thrice year old as his son and 10 year leter he will become twice as his son find their present age with solution
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Answer 1

Answer:

man age is 50 and his son age is 20

Step-by-step explanation:

man age =x

son age=y

x-5=3(y-5)

x+10=2(y+10)

Answer 2

Answer:

let the present age of son be x and father's age be y . the 5 years ago

y-5 = 3(x-5) => y = 3x -10 ....., (1)

10 yrs later

y+10 = 2(x+10) => y = 2x+10 ........(2)

from (1) and (2)

3x-10 = 2x +10

i.e. 3x-2x = 20

i.e. x = 2o . thus y = 2(20) + 10 = 50 (by using (2))

Step-by-step explanation:

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