Question

five year hence the age of Jacob will be three times that of his son 5 years ago a was 7 times that of his son what are their present ages​

Answer 1

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Answer 2

Answer:

let the present age of father be x and the present age of son be y years

5 years hence,father's age = (x+5) years

                        son's age = (y+5) years  

according to the question,

        x+5 = 3(y+5)

        x-3y-10 = 0                          ......i

5 years ago,father's age = (x-5) years

                    son's age = (y-5) years  

according to the question,  

         x-5 = 7(y-5)                

         x-7y+30 = 0                         ......ii

subtracting i from ii,we get

      x-7y+30 = 0

  -   x-3y-10 = 0

or 4y-40=0

or  y = 10

putting the value of y in eqn i , we get

x-30-10=0

or x = 40

hence , present age of father = 40 years

            present age of son = 10 years

hope you will understand it