Question

five years ago A man was 7 times as old as his son 5 years hence the father will be 3 times as old as his son find their present year

Answer 1

let the present age of son be x

let the present age of man be y

caseI: 5 years ago

y-5 = 7(x-5)

y = 7x-35+5

y = 7x-30⇒eq1

caseII: 5 years hence

y+5 = 3(x+5)

y= 3x + 15 - 5

y = 3x+10⇒eq2

from eq1 and eq2

7x-30=3x+10

4x=40

x=10 yrs

y=40 yrs