Question

Five years ago A man was 7 times as old as his son after 5 years he will be thrice as old as his son find their present ages

Answer 1

age of son is 2.5 years and age of father is 17.5 years......

MARK AS BRAINLIEST IF YOU LIKE....

Answer 2

Answer:

Let Five years ago the age of son be x years and age of father be 7x years

Present age of son =x+5

Present age of father =7x+5

5 years later their age will (x+10) and (7x+10)

∴7x+10=3(x+10)

7x−3x=20

4x=20

x=5

So, the present age of son=x+5=5+5=10years

and the present age of father=7x+5=35+5=40years