Question

five years ago A man was 7 times as old as his son after 5 years he will be twice as old as his son find their present age

Answer 1

Answer:

Step-by-step explanation:

Let the past age of son = x

Let the past age of father = 7x

So,

Present ages are x+5 and 7x+5

Future age of son = x+10

Future age of father = 7x+10

Given

7x+10 = 3*(x+10)

7x+10 = 3x+30

7x-3x = 30-10

4x = 20

x = 20/4

x = 5

7x = 35

x+5 = 10

7x+5 = 40