Question

five years ago a man was seven times as old as his son.five years hence the father will be three times as old has his son.find their present ages​

Answer 1

Answer:

let father age=X

five year before=x-5

son age=y

x-5=7y

x=3y

3y-5=7y

-5=-4y

5/4=y

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Answer 2

Answer:

Step-by-step explanation:

Age of the son =x

Age of the father=7x

Present ages=x+5 and 7x+5

future age of the son=x+10

father=7x+10

7x+10=3(x+10)

x=5

7x=35

x+5=5+5=10

son age =10

father age =7x+5=7*5+5=40

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