Question

Five years ago a man was seven times as old as his son. Five years hence, the father will be three time as old as his son. Find there present ages. ​

Answer 1

Answer:

40 and 10

Step-by-step explanation:

Let the age of man 5 yrs ago be x and son be y

  Five yrs ago, x = 7y

  Current age of father = x + 5

                             son = y + 5

  Five yrs after,  x + 10 = 3 [ y + 10 ]

                         7y + 10 = 3y + 30

                               4y = 20

                                  y = 5

                                  x = 35

Present age of father = 40yrs and son = 10 yrs