Question

five years ago a man was seven times as old as his son, while five years hence the man will be four times as old as his son.find their present age ?

Answer 1

Answer. Let the past age of son = xLet the past age of father = 7x So,Present ages are x+5 and 7x+5Future age of son = x+10 Future age of father = 7x+10 Given 7x+10 = 3*(x+10) 7x+10 = 3x+30 7x-3x = 30-10 4x = 20 x = 20/4 x = 5 7x = 35 x+5 = 10 7x+5 = 40
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Answer 2

Answer:

Step-by-step explanation:

Let present age of man=x

Let age of son = y

Five years ago:

Age of man=x-5

Age of son=y-5

Acc. to question:

x-5=7(y-5)

x-5=7y-35...... . . . ......(1)

Five years hence:

Age of man=x+5

Age of son=y+5

Acc. to question:

x+5=4(y+5)

x+5=4y+20...................(2)

Subtracting (2) from(1)

We get,

y=15

Now substituting the value of y in (2)

We get,

x=75

So, present age of man=75 years

And present age of son=15 years