Question

five years ago a man was thrice as old ashis sonand 10 years laterhe shall be twice as old as his son find present age. please guys answer immediately​

Answer 1

Five years ago, Nuri was thrice as old as Sonu. Ten years later, Nuri will be thrice as old as Sonu. How old are Nuri and Sonu?

ANSWER

Five years ago

Age of Nuri = x – 5 years

Age of Sony = y – 5 years

Nuri was thrice as old as Sonu

X- 5 = 3(y – 5)

X – 5 = 35 – 15

X – 3y = -15 + 5

X – 3 y = - 10 ………..(1)

Ten years later,

Age of Nuri = x + 10

Age of Sonu = y + 10

Nuri will be twice as old as Sonu.

X+ 10 = 2(y+10)

X + 10 = 2y + 20

X – 2y = 10 ………..(2)

X – 3 y = - 10 ………..(1)

Subtracting equation (1) from equation (2) we get

Y=20

Plug this value in equation first we get

X−3×20=−10

X = 60 – 10

X=50

Hence age of Nuri=50 years and age of Sonu=20 years

Answer 2

Answer:

Answer:

40

Step-by-step explanation:

Age of the son =x

Age of the father=7x

Present ages=x+5 and 7x+5

future age of the son=x+10

father=7x+10

7x+10=3(x+10)

x=5

7x=35

x+5=5+5=10

son age =10

father age =7x+5=7*5+5=40