Question

Five years ago, A was thrice as old as B and ten years later, A shall be twice as old as B. What are the present age of A and B?

Answer 1

Answer:

Let the present age of B and A be x years and y years respectively. And A's age 5 years ago = (y-5) years. B's age 10 years hence = (x+10)years.

Answer 2

Answer:

A+B=<2X this is the Algebraic expression answer