Question

Five years ago, Anu was thrice as old as Sonu. After ten years, Anu will be twice as old as Sonu. How old are Anu and Sonu. ​

Answer 1

Answer:

Step-by-step explanation:

Let the age of Anu be x years and Sonu be y years.

5 Years Ago,

Age of Anu = x - 5 years

Age of Sonu = y - 5 years

A.T.Q.

( x - 5) = 3(y-5)

= x = 3y - 15 + 5

= x = 3y - 10 _______________(1)

Ten Years Later,

Age of Anu = x + 10 years

Age of Sonu = y + 10 years

A.T.Q.

( x + 10) = 2(y + 10)

= 3y - 10 + 10 = 2y + 20

= 3y - 2y = 20

= y = 20

Substituting ( y = 20) in eq(1).

= x = 3y - 10

= x = 60 - 10

= x = 50

Hence,

Anu's age = x = 50 years

Sonu's age = y = 20 years.

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Answer 2

Answer:

Anu's age is 50 and Sonu's age is 20

Step-by-step explanation:

Let the present age of

Anu be = x

Sonu be = y

Step 1 -

x-5 = 3(y-5)  [substracted five as five years ago]

x-5 = 3y-15  [opening bracket]

x   = 3y-15+5  [transposing 5 to RHS and changing - to +]

x   = 3y-10  [value of x]

Step 2 -

      x+10 = 2(y+10)  [added 10 as after ten years]

      x+10 = 2y+20  [opening bracket]

3y-10+10 = 2y+20 [adding value of x as per step 1]

    3y-2y = 20  [transposing 2y to LHS and changing + to -]

           y = 20 [value of y and age of Sonu]

Step 3 -

x = (3×20)-10 [using the value of x and y]

x = 60-10

x = 50  [Age of Anu]

Hence, Anu is 50 years old and Sonu is 20 years old.