Question

Five years ago daughter's age was 8 years more than son's age.now ,daughter's age is only two times as son's present age .find their present ages.

Answer 1

Answer:

Son's present age is 8, daughter's present age is 16  

Step-by-step explanation:

d - 5 = (s - 5) + 8

d - 5 = s + 3

d = s + 8

d = 2s

2s = s + 8

s = 8

d = 16

Answer 2

Question

Five years ago daughter's age was 8 years more than son's age. now ,daughter's age is only two times as son's present age .find their present ages.

Solution

Given :-

• Five years ago daughter's age was 8 years more than son's age.
• Now ,daughter's age is only two times as son's present age

Find :-

• Present age of daughter & Son

Explanation

Let,

• Age of daughter = x years
• Age of Son = y years

A/c to question

( Five years ago daughter's age was 8 years more than son's age )

==> (x - 5 ) = (y -5) + 8

==> x - y = -5 + 5 + 8

==> x - y = 8 ------------Equ(1)

Again,

(Now ,daughter's age is only two times as son's present age)

==> x = 2y

==> x - 2y = 0 ---------------Equ(2)

Subtract equ(1) & equ(2)

==> -y + 2y = 8

==> y = 8

Keep Value of y in equ(2)

==> x - 2*8 = 0

==> x = 16

Hence

• present Age of Daughter (x) = 16 years
• Present Age of Son (y) = 8 years

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