Question

five years ago,lucky was three times as old as lovely. 10 years later, lucky would be twice as old as lovely. how old are they now...?​

Answer 1

let x be lucky's age and y be lovely's age presently.

so five years ago,

                x - 5 = 3 (y -5)

                x - 5 = 3y -15

                x = 3y - 10

ten years later,

               x + 10 = 2 ( y + 10)

               x + 10 = 2y + 20

               x  = 2y + 10

since you see that x = 3y - 10 and x = 2y + 10, then,

             3y - 10 = 2y + 10

             3y = 2y + 20

              y = 20

sub this value into x = 2y + 10

             x = 2 (20) + 10

             x = 50

so, Lucky is 50 and Lovely is 20 now.

Answer 2

❣️❣️Hey mate ❣️❣️

Here is the solution :-

Five years ago :-

Age of lovely = X years

Thus,

Age of lucky = 3x years

10 years later :-

age of lovely = x + 10 years

age of lucky = (3x + 10 ) years

According to the question :-

3x + 10 = 2(x + 10)

3x + 10 = 2x + 20

3x - 2x = 20 - 10

x = 10

Present age of lovely = 10 + 10 = 20 years

present age of lucky = 3x + 10 = 40 years

Hope it will help you...

mark it as a brainleist...❣️❣️❣️