Question

five years ago lucky was three times as old as lovely at that time .10 years later would be twice as old as lovely .how old they are now.?

Answer 1

let lovely age be x
lucky age = y

5 years ago

y - 5 = 3( x-5)
y- 5 = 3x - 15

y - 3x = -10

10 years later

y+ 10 = 2( x+10)

y + 10 = 2x + 20
y -2x = 10

subtract eq 2 from 1
-x = -20

x = 20

y - 40 = 10
y= 50

Answer 2

Answer:)

Step-by-step explanation:(