five years ago Nuri was thrice as old as sum 10 years later no he will be twice as old as sum how old are nuri and sonu
Answers
- five year's ago Nuri was thrice as old as Sonu.
- 10 year's later Nuri will be twice as old as Sonu.
- Present ago of Nuri and Sonu.
- Let the present age of Nuri be x year.
- Let the present age of Sonu be y year.
✰ five year age Nuri was thrice as old Sonu.
Nuri Age ⇢(x - 5) year's
Sonu Age ⇢ (y - 5) year's
»★ According to 1st condition:
⟹ (x - 5) = 3(y - 5)
⟹ (x - 5) = 3y - 15
⟹ x - 3y = -10 ...........(1)
✰ 10 year later Nuri will be twice as old as Sonu.
- Nuri Age ⇢(x + 10) year's
- Sonu Age ⇢ (y + 10) year's
»★ According to 1st condition:
⟹ (x + 10) = 2(y + 10)
⟹ x + 10 = 2y + 20
⟹ x - 2y = 10 .........(2)
✰ from Eq (1) and Eq (2), we get.
x - 3y = - 10
x - 2y = 10
- + -
______________
-y = -20
✰ Putting the value of y in Eq. (1)
⟹ x - 3y = -10
⟹ x - 3 × 20 = -10
⟹ x - 60 = -10
⟹ x = -10 + 60
⟹ x = 50
Hence,
- Nuri Age is x = 50 year
- Sonu Age is y = 20 year
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Answer:
Step-by-step explanation:
Let the present age of Nuri be x years.
Let the present age of Sonu be y years.
Case 1: 5 years ago:
Age of Nuri = x - 5 years
Age of Sonu = y - 5 years
It is given that 5 years ago, the age of Nuri was 3 times that of Sonu. Putting it in the form of an equation, we get:
x - 5 = 3(y - 5)
x - 3y = -10 (1)
Case 2: 10 years later:
Age of Nuri = x + 10 years
Age of Sonu = y + 10 years
It is given that 10 years later, the age of Nuri will be 2 times that of Sonu. Putting it in the form of an equation, we get:
x +10 = 2(y + 10)
x - 2y = 10 (2)
We need to solve equation (1) and (2) simultaneously:
(1) x - 3y = -10
(2) x - 2y = 10
Now, in (1), we have:
x = -10 + 3y
Substituting the value of x from (1) in (2), we get:
-10 + 3y -2y = 10
y = 20
y = 20
Putting this value of y in equation (1), we get:
x - 3(20) = -10
x = 50
Hence, the present age of Nuri is 50 years and the present age of Sonu is 20 years