five years ago Sagar was thrice as old as tinu. 10 years later sagar's age will be 20 years more than tinu's age. find their present age, what was the age of Sagar when tinu was born
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this is the answer
- Safar age = x
- tinu age = y
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The present age of Sagar and Tinu are 35 and 15 respectively.
the age of Sagar when tinu was born was 20.
Let the present age of Sagar be x and Tinu's be y.
5 years ago,
Sagar's age was (x-5)
Tinu's was (y-5)
Given that, Sagar was thrice as old as Tinu.
So, (x-5) = 3(y-5)
⇒ x - 5 = 3y - 15
⇒ x = 3y - 10 ...(1)
10 years later from now,
Sagar's age will be (x+10)
Tinu's age will be (y+10)
Given, Sagar's age will be 20 years more than Tinu's age.
So, (x+10)-(y+10) = 20
⇒ x - y = 20 ...(2)
Substituting the value of x from (1), we get:
3y - 10 - y = 20
⇒ 2y = 30
⇒y = 15
x = 3y - 10 = 45 - 10 = 35
Present ages of Sagar and Tinu are 35 and 15 respectively.
When Tinu was born, i.e. 0 years old, we substitute y = 0 in eqn.(2), we get
x = 20
Sagar was 20 years old.
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