Five years ago, seeta was thrice as old as geeta and ten years later seeta shall be twice as old as geeta.find their present ages?
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let age of Seeta=x
Geeta=y
x-5=3(y-5)
x+10=2(y+10)
by subtracting
-15=y-35
y=20
x=50
Geeta=y
x-5=3(y-5)
x+10=2(y+10)
by subtracting
-15=y-35
y=20
x=50
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