Question

five years ago sunil was twice as old as monu . ten years later sunils age will be 10 years more than monu age find their present ages graphically​

Answer 1

Answer:

$sunil's \: age \: = 20 \\ monu's \: age = 35$

Step-by-step explanation:

Let, Sunil's age be $x$.

Five years ago,

Sunil's age=$x-5$

Monu's age= $2(x-5)$

ten years later,

Sunil's age =$10+monu's age$

$(x + 10) + 10 = 2(x - 5) + 10$

$x + 20 = 2x - 10 + 10$

$x = 20$

$sunil \: age \: = 20 \\ monu \: age = 35$

Answer 2

sunil=a,monu=b

a-5=2(b-5)

a-5=2b-10

a+10-5=2b

a+5 =2b

10yrs later

a+10=(b+10)+10

a+10=b+20

a=b+20-10

a=b+10

put d value in first equation

a+5=2b

b+10+5=2b

2b-b=15

b=15

a=b+10

a=15+10=25

sunil age=25,monu age=15