Question

five years ago, Sunil was twice as old as Monu.
Ten years later
later, Sunil's
age
will be 10 years
more than Monu's age. Find present ages by
graphically.​

Answer 1

Answer:

hope this helps u :-)

Step-by-step explanation:

Let say present age of sunil = S Years

Let Say present age of monu = M  Years

Five year Ago Sunil's Age = S - 5

Five year Ago monu's  Age = M - 5

Five years ago, Sunil was twice as old as monu.

S -5 = 2(T-5)

=> S - 5 = 2T - 10

=> 2T = S + 5

Ten year Later Sunil's Age = S + 10

Ten year Later monu Age = T + 10

S + 10 = T + 10 + 10

=> S = T + 10

2T = S + 5

=> 2T = T + 10 + 5

=> T = 15

S = 15 + 10 = 25

monu Present age = 15 Years

Sunil Present age = 25 Years

Answer 2

Answer:

15 and 25 year old

follow me on the answer and mark as brainliest