Math, asked by ankits44394, 10 months ago


Five
years
hence, bovita
age
will be two times
the age of his borthero years ago she was o
times
as old as his hot brother represent fvo situation
algebrically and graphically​

Answers

Answered by TheWorker
1

SOLUTION = Let 'x' be the present age of jacob and 'y' be the age of his son

Let 'x' be the present age of jacob and 'y' be the age of his sonAs per question

Let 'x' be the present age of jacob and 'y' be the age of his sonAs per questionx+5=3(y+5).....(1)

Let 'x' be the present age of jacob and 'y' be the age of his sonAs per questionx+5=3(y+5).....(1)x−5=7(y−5).......(2)

Let 'x' be the present age of jacob and 'y' be the age of his sonAs per questionx+5=3(y+5).....(1)x−5=7(y−5).......(2)Adding (1) and (2)

Let 'x' be the present age of jacob and 'y' be the age of his sonAs per questionx+5=3(y+5).....(1)x−5=7(y−5).......(2)Adding (1) and (2)2x=3y+15+7y−35

Let 'x' be the present age of jacob and 'y' be the age of his sonAs per questionx+5=3(y+5).....(1)x−5=7(y−5).......(2)Adding (1) and (2)2x=3y+15+7y−352x=10y−20

Let 'x' be the present age of jacob and 'y' be the age of his sonAs per questionx+5=3(y+5).....(1)x−5=7(y−5).......(2)Adding (1) and (2)2x=3y+15+7y−352x=10y−20x=5y−10...(3)

Let 'x' be the present age of jacob and 'y' be the age of his sonAs per questionx+5=3(y+5).....(1)x−5=7(y−5).......(2)Adding (1) and (2)2x=3y+15+7y−352x=10y−20x=5y−10...(3)Putting (3) in (1)

Let 'x' be the present age of jacob and 'y' be the age of his sonAs per questionx+5=3(y+5).....(1)x−5=7(y−5).......(2)Adding (1) and (2)2x=3y+15+7y−352x=10y−20x=5y−10...(3)Putting (3) in (1)5y−5=3y+15

Let 'x' be the present age of jacob and 'y' be the age of his sonAs per questionx+5=3(y+5).....(1)x−5=7(y−5).......(2)Adding (1) and (2)2x=3y+15+7y−352x=10y−20x=5y−10...(3)Putting (3) in (1)5y−5=3y+152y=20

Let 'x' be the present age of jacob and 'y' be the age of his sonAs per questionx+5=3(y+5).....(1)x−5=7(y−5).......(2)Adding (1) and (2)2x=3y+15+7y−352x=10y−20x=5y−10...(3)Putting (3) in (1)5y−5=3y+152y=20y=10

Let 'x' be the present age of jacob and 'y' be the age of his sonAs per questionx+5=3(y+5).....(1)x−5=7(y−5).......(2)Adding (1) and (2)2x=3y+15+7y−352x=10y−20x=5y−10...(3)Putting (3) in (1)5y−5=3y+152y=20y=10Putting in (3)

Let 'x' be the present age of jacob and 'y' be the age of his sonAs per questionx+5=3(y+5).....(1)x−5=7(y−5).......(2)Adding (1) and (2)2x=3y+15+7y−352x=10y−20x=5y−10...(3)Putting (3) in (1)5y−5=3y+152y=20y=10Putting in (3)x=5×10−10

Let 'x' be the present age of jacob and 'y' be the age of his sonAs per questionx+5=3(y+5).....(1)x−5=7(y−5).......(2)Adding (1) and (2)2x=3y+15+7y−352x=10y−20x=5y−10...(3)Putting (3) in (1)5y−5=3y+152y=20y=10Putting in (3)x=5×10−10x=40

Let 'x' be the present age of jacob and 'y' be the age of his sonAs per questionx+5=3(y+5).....(1)x−5=7(y−5).......(2)Adding (1) and (2)2x=3y+15+7y−352x=10y−20x=5y−10...(3)Putting (3) in (1)5y−5=3y+152y=20y=10Putting in (3)x=5×10−10x=40Therefore Present age of Jacob is 40 years and his son is 10 years.

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