Question

Five years hence the age of a man shall be three times the age of his son while five years earlier the age of the man was 7 times the age of his son the present age of the man is

Answer 1

Let the past age of son = x

Let the past age of father = 7x

So,

Present ages are x+5 and 7x+5

Future age of son = x+10

Future age of father = 7x+10

Given

7x+10 = 3*(x+10)

7x+10 = 3x+30

7x-3x = 30-10

4x = 20

x = 20/4

x = 5

7x = 35

x+5 = 10

7x+5 = 40

Answer 2

Answer:

Step-by-step explanation:LET THE MANS AGE BE X AND THE SONS AGE BE Y

5+x=3(y+5)

5+x= 3y +15

x-3y= 10---------------1

x-5=7(y-5)

x-5=7y-35

x-7y= -30----------------2

equating 1 and 2 we get,

y=10yrs

x= 10+3*10

=10+30

=40yrs