Five years hence, the age of jacob will be three times that of his son. five years ago, jacob's age was seven times that of his son. what are their present ages?
Answers
Answer:
Step-by-step explanation:
Let the present age of Jacob = 'x' year
And present Age of his son is = 'y' year
Five years hence,
Age of Jacob will be = x + 5 year
Age of his son will be= y + 5year
Given that the age of Jacob will be three times that of his son
x + 5 =3(y+5)
Add 5 both side we get
x = 3y + 15 - 5
x = 3y + 10 … (1)
Five years ago,
Age of Jacob will be = x - 5 year
Age of his son will be = y - 5year
Jacob’s age was seven times that of his son
x – 5 = 7(y -5)
Plug the value of x from equation (1) we get
3y + 10 – 5 = 7 y – 35
3y +5 = 7y – 35
3y – 7 y = - 35 – 5
-4y= - 40
y = - 40 / - 4
y = 10 year
Plug the value of y in equation first we get
x= 3* 10 + 10
x= 40 years
Thank you
Hope it's correct
Answer:
Please refer to the attachment
