Question

five years hence, the age of John will be three times that of his daughter. Five years ago, John's age was seven times that of his daughter. what are their present ages.​

Answer 1

Answer:

let the present age of john be x and that of his daughter be y.

from first condition,

x+5=3(y+5)

x+5=3y+15

x-3y=15-5

x-3y=10............. (1)

From second condition,

x-5=7(y-5)

x-5=7y-35

7y-x=30........(2)

adding one and two we get,

y=10 and x=40

therefore, John present age is 40 years and his daughter is 10 years