Five years hence the age of money should be three times that of his son 5 years ago manish age was seven times that of his son what are their present ages
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Answer:let money 's age be x
Let son 's age be y.
ATQ five years hence
Money age =x+5
Son age =y+5 then
X+5= 3( y+5)
X+5= 3y+15
x-3y=10.let equation (a)
And then
X-5=7(y-5)
X-5= 7y-35
X-7y =-30 let equation b.
Then solve equation a and b by elimination method
X-7y=-30
X-3y=10
_ + -
-4y =- 40
Y= 10 so present age of son is 10 years
Put value of y I equation a then find value of x
X-3y=10
X-3( 10) = 10
X-30=10
X= 40
So present age of father is 40 years.
Step-by-step explanation:
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