Question

FIXATION
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What I Can Do
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Let us see how the second law is applied to the problems below.
Problem 1
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A boy pushed horizontally a 3.5 kg plastic chair across the slippery floor. If
exerted on the plastic chair?
the acceleration of the plastic chair is 2.2 m/s2 to the left, what is the net force
Given:
kg
m/s?, to the left
Find:
ΣΕ
Formula: EA má​

Answer 1

F=ma

m=3.5 kg

a=2.2 m/s²

So force can be calculated as

F= 3.5 × 2.2

  =7.7 N

Answer 2

Given:

$\begin{array}{l}m=3.5 \mathrm{~kg} \\\vec{a}=2.2 \mathrm{~m} / \mathrm{s}^{2} \text { to the left }\end{array}$

To find

$\begin{aligned}& \vec{F} \\\sum \vec{F} &=m \vec{a} \\&=(3.5 \mathrm{~kg})\left(2.2 \mathrm{~m} / \mathrm{s}^{2}\right) \\&=7.7 \mathrm{~kg} \mathrm{~m} / \mathrm{S}^{2} \text { to the left }\end{aligned}$

The net force extended on the plastic chair is

$\varepsilon \vec{F}=7.7 \mathrm{~kg} \mathrm{~m} / \mathrm{s}^{2}$