Question

Flask x contains 5dm3 of helium at 12kpa pressure and flask y contains 10dm3 of neon at 6kpa pressure. If the flasks are connected at constant temperature, what is the final pressure?

Answer 1

Answer:

$P_{1}$*$V_{1}$=$P_{2}$*$V_{2}$

$P_{2} =\frac{P_{1}*V_{1}  }{V_{2} }$

The final volume=15L

The partial pressure of the helium decreases to $\frac{12*5}{15} =4kPa$

The partial pressure of the Neon to $\frac{6*10}{15} =4kPa$

Then the final pressure will be the sum of the two partial pressures=8kPa

Answer 2

Answer:8kPa

Explanation:

To answer this question we must know the formula P1*V1=P2*V2.

Rearrange the formula to find the final pressure. The total volume is 15 dm3, P1*V1/15.

Partial pressure of Helium: 12*5/15 = 4kPa

Partial pressure of Neon: 10*6/15 = 4kPa

Add both of them 4+4=8 .

Therefore 8kPa is the combined pressure at constant temperature.