Question

Flower Garden Prabhjot developed a rectangular flower garden. 16 flower pots were placed at a distance of 1m from each other along both side of garden as shown in Figure. Prabhjot drew 11 parallel vertical lines between two sides for better placement of pots. He brought 6 new decorative plants. He placed 5 pots (A,B,C,D and E) at position indicated in figure. a)What is the distance between pot A and pot B
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Answer 1

Given : Prabhjot developed a rectangular flower garden. 16 flower pots were placed at a distance of 1m from each other along both side of garden as shown in Figure

Prabhjot drew 11 parallel vertical lines between two sides for better placement of pots. He brought 6 new decorative plants. He placed 5 pots (A,B,C,D and E) at position indicated in figure.

To Find :  a)What is the distance between pot A and pot B

b) Which geometrical figure is formed by pots A,B,C and D?

c) Prabhjot wants to place pot F exactly in between Pots A(2,4) and C (8,10). Where should he place it ?

d) What is distance between pots B and E?

Solution:

A  = ( 2 , 4)

B = ( 2 , 10)

C = ( 8 , 10)

D = ( 8 , 4)

E = ( 5 , 15)

distance between pot A and pot B

A  = ( 2 , 4) , B = ( 2 , 10)

= √(2 - 2)² + ( 10 - 4)²

= 6 m

distance between pot A and pot B = 6 m

geometrical figure is formed by pots A,B,C and D

AB = BC = CD = AD = 6 m

& lines are perpendicular

SQUARE is formed

Pot F exactly in between Pots A(2,4) and C (8,10).

= (2 + 8)/2 , ( 4 + 10)/2

= 5 , 7

distance between pots B and E

B = ( 2 , 10) , E = ( 5 , 15)

√(5 - 2)² + ( 15 - 10)²  

√9 + 25

= √34 m

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Answer 2

Answer:

6

Step-by-step explanation:

If we look at the diagram, we are given a diagram with a proper scale mentioned on along its vertical and horizontal axis.

In the question statement, we are to dertermine the distance between flower pot A and B.

Now there are two ways, one way is to count the units between A and B. If we count them, these are 6 units.

Other way is use the distance formula between straight lines which will be;

A = (2,4)

B =(10,4)

= $\sqrt{(2-2)^2 + (10-4)^2}$

= 6