Question

Fluorine acts as the strongest oxidizing agent among the halogens, explain

Answer 1

Halogens have high electronegativity and electron affinity. They have greater tendency to accept electrons or easily reduced, therefore they are strong oxidizing agent.
As the reduction potential decrease down the group,the oxidizing power decrease down the group the order of the oxidizing power will be as under
F2 > Cl2> Br2> I2
¥ The oxidizing power depends on,
Heat of dissociation of halogen molecule.
Electron affinity of atom.
Hydration energy of the ion.
Heat of vaporization
If a halogen has low energy of dissociation, a high electron affinity, and higher hydration of its ion, it will have high oxidizing power.
F has although low electron affinity than Cl but low dissociation energy and have high hydration energy of its ion, therefore Fluorine is strongest oxidizing agent.

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Answer 2

Answer:

Fluorine is more electronegative than chlorine therefore it can attract a share pair of electron more easily and strongly than chlorine. Thus, it can easily accept the pair of electrons and undergoes reduction. Thus it is a strong oxidising agent than chlorine.

Explanation:

all halogen are oxidization agent ,

however reactivity decrease down the group those fluorine is a strong oxidizing agent and Iodine is the weakest. this is mainly due to electron gain enthalpy become less negative as we go down the group however as we know electron gain enthalpy of fluorine is an expectedly less negative as compare to chlorine despite this fact fluorine is a strong oxidizing agent and chlorine fluorine can oxidize other halide Ion even in a solid state .

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