focal length of the comcave lens is 20cm an object is placed 15cm distance from the pole find the image distamce height of the image and mention the characteristics of the image
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Answered by
2
Answer:
f= -20cm
u= -15cm
v= ?
1/v - 1/u = 1/f
therefore, 1/v = 1/f + 1/u
1/v = 1/-20 + 1/-15
1/v = 1/-20 - 1/15
1/v = (-3-4)/60 (by taking LCM)
1/v = -7/60
v = -60/7
v = -8.57(approx)
the image formed by lense is
real and inverted
thanks for your....
Answered by
4
given, focal length of concave mirror, f = -20 cm
distance of object from the mirror, u = -10 cm
use formula, 1/v + 1/u = 1/f
or, 1/v = 1/f - 1/u
or, 1/v = 1/-20 - 1/-10
or, 1/v = -1/20 + 1/10 = 1/20
or, v = +20cm
hence, image position is 20cm right side from the pole of concave mirror
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