Focused 20 cm from the lens. when a
diverging lens is placed in contact with the
converging lens, the rays are for 30 cm from
the combination. what is the focal length of
the diverging lens.
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Answer:
Given,
Focal length of converging lens, f1=20 cm
Focal length of diverging lens,f2=−5 cm
feq=f1+f2−df1f2
Since there is no deviation,
feq=∞
⇒f1+f2−d=0
⇒f1+f2=d
20−5=d
⇒d=15 cm
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