Question

FOLLOW0nY
1) x²-x-K, Find the value of k if 4 is the
zeros of polynomial​

Answer 1

Answer:

put x=4,

x²-x-k=0

4²-4-k=0

16-4-k=0

12-k=0

-k=0-12

-k=-12

k=12

Answer 2

$Let \: p(x) = x^{2} - x - k$

$Given \: 4 \: is \: a \: zero \: of \: p(x)$

$p(4) = 0$

$\implies 4^{2} - 4 - k = 0$

$\implies 16 - 4 - k = 0$

$\implies 12 - k = 0$

$\implies - k = -12$

$\implies k = 12$

Therefore.,

$\red{ Value \: of \: k } \green { = 12 }$

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