Physics, asked by navya2105, 7 months ago

The pressure of sea water with the depth
200 m, mean density 1032 x 103 kg/m and
g = 10 m/s2 is
(a) 3.023 x 10' N/m²
(b) 2.06 x 104 N/m2
(c) 1.025 x 105 N/m
(d) 2.064 x 10' N/m2

Answers

Answered by Anonymous
1

Explanation:

The gauge pressure at any depth is given by,

P

g

=ρgh

Given, the atmospheric pressure to be P

o

=1.013×10

5

Pa

The pressure at this depth will be,

P=P

o

+P

g

= 1.013×10

5

+1.03×10

3

×10×200

= 21.2×10

5

Pa

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