Question

Following compounds are given:
(i) CH₃CH₂OH (ii) CH₃COCH₃
(iii) CH₃ - CHOH
|
CH₃
(iv) CH₃OH
Which of the above compound(s), on being warmed with
iodine solution and NaOH, will give iodoform?
(a) (i) and (ii) (b) (i), (iii) and (iv)
(c) only (i) (d) (i), (ii) and (iii)

Answer 1

Explanation:

I think the correct answer is (d)

Answer 2

(i), (ii) and (iii) will give haloform reaction.

Explanation:

• The haloform reaction is a reaction of a compound with a halogen and concentrated alkali giving a haloform reaction.

• This is not only a reaction but also a test.

• Only the ketones with alpha methyl group and secondary alcohol with alpha methyl group gives this test.

• Ethanol is only exception where the primary alcohol gives haloform positive.

• Here in option 1, we can see ethanol which is haloform positive.

• In option 2, we can see acetone which is a alpha methyl ketone, so gives haloform positive.

• In option 3 we can see the propan 2 ol which is a secondary alcohol with alpha methyl group, so gives haloform positive.

• In option 4, there's methyl alcohol which is primary alcohol, so don't give haloform positive reaction.

For more information about haloform reaction,

https://brainly.in/question/4078512

Why acetic acid does not show haloform reaction? - Brainly.in

https://brainly.in/question/2556214

A ketone A which undergoes haloform reaction gives a compound B on reduction . B on heating with sulphuric acid gives a compound C which forms monoozonide D. D onhydrolysis in the presence of zinc dust gives only acetaldehyde. identify A, B, C, and D. write down the reactions involved.