Following figure shown a cubical block with a slot in it. There is a small block held in the slot
against a spring. The value of acceleration of the cubical block for which there is no extension
compression in the spring is
1) g
100002
2) g cot
3) g tan
a
g
4)
cos
101
TARGET SERIES for Sri Chaitanya Jr. ICON Students
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Asked on December 27, 2019 by
Zainab Modak
In the figure shown C is a fixed wedge. A block B is kept on the inclined surface of the wedge C. Another block A is inserted in a slot in the block B as shown in figure. A light inextensible string passes over a light pulley which is fixed to the block B through a light rod. One end of the string is fixed and other end of the string is fixed to A.S is a fixed support on the wedge. All the surfaces are smooth. Masses of A and B are same. Then the magnitude of acceleration of A is
3
x
m/s
2
. Then x is (sin37
∘
=3/5).
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ANSWER
Lets find relation between accelerations of two blocks using string constrain.
x+y=L
Differentiating twice w.r.t time.
a
A
+a
B
=0
let a be the magnitude of acceleration for block B.
2mgsinθ−T=2ma→(1)
For block A
T−mgcosθ=ma→(2)
From here we can get,
T=
15
14mg
acceleration of A=
3
4
ms
−2
acceleration of B=
3
4
ms
−2
So, resultant acceleration of A is
a
A
=
(
3
4
)
2
+(
3
4
)
2
a
A
=
3
32
ms
−2