Question

fond the values of a&b if (x-2)(x-2) are factors of x cube -ax+b​

Answer 1

Answer:

${x}^{2} - ax + b = (x - 2)^{2} \\ let \: solve \: (x - 2) ^{2} \\ {x}^{2} - 2 \times 2 \times x + {2}^{2} \\ = {x}^{2} - 4x + 4 \\ then \\ a = - 4 \\ b = 4$

Answer 2

(x-2)2= x2-2×x×2+(2)2×x

=x2-4x+4

=x2-ax+b

a=-4

b=+4