Math, asked by Diya974, 9 months ago

Foot of a 20m long ladder leaning against a vertical wall is 12m away from the base of the wall. Find the height of the point on the wall where the top of the ladder reaches.

Answers

Answered by yoshanachaudhary
3

Answer:

By Yoshana Chaudhary

Step-by-step explanation:

Answer is 14m by pythagoras theorem...hypotenuese is 20m and base is 12m so (20)^2=(12)^2+Height^2

400m=144m+h^2

400m-144m=h^2

256=H^2

h=root 256

h=14m

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Here it is....Marks as brianlliest if its right

Answered by Anonymous
1

Let PR be the ladder and QR be the vertical wall.

Length of the ladder PR = 10 m

PQ = 6 m

Let height of the wall, QR = h

According to Pythagoras theorem,

PR2 = PQ2+QR2

102 = 62+QR2

100 = 36+QR2

QR2 = 100-36

QR2 = 64

Taking square root on both sides,

QR = 8

Hence the height of the wall where the top of the ladder reaches is 8 m.

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