Question

for √2x²-5x+√2=0 find the value of discriminant​

Answer 1

Step-by-step explanation:

The given equation is √2x²—5x+√2 = 0.

This equation is of the form of ax²+bx+c = 0.

WHere,

a = √2

b = —5

c = √2

Now, discriminant

D= (b²—4ac)

D= {(—5)²—4×√2×√2}

D = 25—4×√4

D = 25—4×2

D = 25—8

D = 17

Hence, the discriminant of the equation is 17.

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Answer 2

For √2x² - 5x + √2 = 0 the value of discriminant = 17

Given :

The quadratic equation √2x² - 5x + √2 = 0

To find :

The Discriminant of the equation

Concept :

General form of a quadratic equation is

ax² + bx + c = 0

The Discriminant of the quadratic equation is denoted by D and defined as

D = b² - 4ac

Solution :

Step 1 of 2 :

Write down the given equation

The given Quadratic equation is

√2x² - 5x + √2 = 0

Step 2 of 2 :

Find the value of discriminant

Comparing with the general equation of quadratic equation ax² + bx + c = 0 we get

a = √2 , b = - 5 , c = √2

Value of Discriminant

$\sf = {b}^{2} - 4ac$

$\sf = {( - 5)}^{2} - 4 \times \sqrt{2} \times \sqrt{2}$

$\sf = 25 - 8$

$\sf = 17$

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