Question

For 71th republic day Parade on 26/01/2021 in Delhi, Captain RS Meel is planning for parade of following two groups: (1) First group of Army contingent of 624 members behind an army band of 32 members. (2) Second group of CRPF troops with 468 soldiers behind the 228 members of bikers. These two groups are to march in the same number of columns. This sequence of soldiers is followed by different states of Jhanki which are showing the culture of the respective states. (i) What is the maximum number of columns in which the army troop can march? a) 8 b) 16 c) 4 d) 32 (ii) What is the maximum number of columns in which the CRPF troop can march? a) 4 b) 8 c) 12 d) 16 (iii) What is the maximum number of columns in which total army troop and CRPF troop together can march past? a) 2 b) 4 c) 6 d) 8​

Answer 1

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Answer 2

Answer:

HCF (616,32) is the maximum number of columns in which they can march.

Step 1: First find which integer is larger.

616>32

Step 2: Then apply the Euclid's division algorithm to 616 and 32 to obtain

616=32×19+8

Repeat the above step until you will get remainder as zero.

Step 3: Now consider the divisor 32 and the remainder 8, and apply the division lemma to get

32=8×4+0

Since the remainder is zero, we cannot proceed further.

Step 4: Hence the divisor at the last process is 8

So, the H.C.F. of 616 and 32 is 8.

Therefore, 8 is the maximum number of columns in which they can march.