Question

For 9 innings, Roman has an average of 65 runs. In the tenth inning, he scores 200 runs, thus increasing his average . His average increased by ?​

Answer 1

Answer:

hi

your answer is here !

Step-by-step explanation:

Total score for 65 innings = 65×9 = 585

Total score after 10th innings = 585 + 200 = 785

So, the new average is 785/10 = 78.5

So, the increment is of 13.5

$follow \: \: \: me$

Answer 2

Given :

• Number of innings (initially) = 9
• Average Score in 9 innings = 65 runs
• He scored 200 runs in 10th inning

To FinD :

• His increased Average

SolutioN :

Use formula for Average :

$\implies \sf{Average \: Score \: = \: \dfrac{Total \: Score}{No. \: of \: innings}} \\ \\ \implies {\sf{65 \: = \: \dfrac{Total \: Score}{9}}} \\ \\ \implies \sf{Total \: score \: = \: 65 \: \times \: 9} \\ \\ \implies \sf{Total \: score \: = \: 585} \\ \\ \underline{\sf{\therefore \: Total \: score \: till \: 9 \: innings \: is \: 585 \: runs}}$

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If he scores 200 runs in 10th inning, then

$\implies \sf{Total \: score \: = \: 585 \: + \: 200} \\ \\ \implies \sf{Total \: score \: = \: 785}$

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Now, average score of 10 innings will be :

$\implies \sf{Average \: = \: \dfrac{Total \: score}{No. \: of \: innings}} \\ \\ \implies \sf{Average \: = \: \dfrac{785}{10}} \\ \\ \implies \sf{Average \: = \: 78.5} \\ \\ \underline{\sf{\therefore \: Average \: runs \: in \: the \: 10 \: innings \: is \: 78.5}}$

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How much His Average is increased

$\implies \sf{Avg_{increased} \: = \: Avg_{Final} \: - \: Avg_{initial}} \\ \\ \implies \sf{Avg \: = \: 78.5 \: - \: 65} \\ \\ \underline{\sf{\therefore \: Increase \: in \: Average \: is \: 13.5}}$