Question

For a b c in R and a b c are different; then the roots of (x+a)(x+b)=c^(2) are​

Answer 1

Answer:

for ax  

2

+bx+c=0

α<−1 and β>1

Therefore, f(−1)f(1)<0

Therefore, ⇒(c+b+a)(c−b+a)<0

⇒  

a

c

​  

+  

∣

∣

∣

∣

∣

​  

 

a

b

​  

 

∣

∣

∣

∣

∣

​  

<−1

Step-by-step explanation: