Question

For a body of mass 2.0 kg moving in a straight line, the graph of its distance x from the starting point --> time t is shown in the figure. Find the value of impulse of force at (i) t = 2s and (ii) t = 6 s for very small time intervals.

Answer 1

Part i )M=2.0 s=x t=2s u=20m/s v=0 a=v-u/t=0-20/10= -10m/s*2 s=ut+1/2at*2 x=20×2+1/2×-10×2×2 x=20m  Force = ma  =2.0× -10 = -20N  Impulse =Force ×time  = -20 ×2 =-40Ns Don't know second part