For a cell of e.m.f. 2 V, a balance is obtained for 50 cm of the potentiometer wire. If the cell is shunted by a 2 ohm resistor and the balance is obtained across 40 cm of the wire, then the internal resistance of the cell is *
2 points
(a) 1 ohm
(b) 0.5 ohm
(c) 1.2 ohm
(d) 2.5ohm
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Option 2 is the right answer. Hope this answers your question.
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